The law sines states for any triangle with sides A,B, or C that
sin(a)/A = sin(b)/B = sin(c)/C
or equivalently
A/sin(a) = B/sin(b) = C/sin(c)
So if we have a triangle as such, with side x unknown we can find it by using the law of sines:
Proof of the Law of Sines
Consider the following diagram:
In the first step of the proof we divide the triangle into two right triangles by drawing a line of length h1.
Now we have two right triangles we can say that
sin(b)=h/A or h=A*sin(b)
similarly
sin(a)=h/B so h=B*sin(a)
now we can see that
B*sin(a)=h=A*sin(b)
divide both sides by AB and we get
sin(a)/A = sin(b)/B which is the first half of the law of sines.
For the next part, we draw a right triangle out from side B, creating a new length h2.
From this new triangle we see that
sin(b)=h/C and h=sin(b)*C
we also see that
sin(180-c) = h/B or h=sin(180-c)*B
but from the unit circle below we see that sin(180-c)=sin(c)
so we can write sin(c)*B=h and from this conclude
sin(b)*C=h=sin(c)*B
again we divide both sides by BC and get
sin(b)/B = sin(c)/C
so we have sin(a)/A=sin(b)/B=sin(c)/C which is the law of sines.
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