P(E) + P(not E) = 1

This is because the probability of any event in the sample space must equal 1. Therefore if we know the probability of E we can also find the probability of not E.

Thus if we want to know the probability of not rolling a 2 on an even die we can say

P(rolling a 2) = 1/6

1/6 + P(not rolling a 2) = 1

P(not rolling a 2) = 1 - (1/6) = (5/6)

## Tuesday, February 17, 2009

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