Prove that sin^2(x) + cos^2(x) = 1
by Pythagorean Theorem A^2 + O^2 = H^2
Now, if we divide both sides by H^2 we get
(A^2 + O^2)/H^2 = H^2/H^2
which is
A^2/H^2 + O^2/H^2 = 1
which is
(A/H)^2 + (O/H)^2 = 1
now sin(x) = A/H and cos(x)=O/H so
sin^2(x) + cos^2(x) = 1
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