(4x

^{2}- 4)=0 is by factoring and setting both factors equal to zero. Because a quadratic contains a x

^{2}they often have two solutions.

(4x

^{2}- 4)=0 can be factored to

(2x - 2)(2x + 2)=0

Now set both factors equal to zero

2x-2=0

2x+2=0

we get

x=1 and x=-1

substituting 1 or -1 for x will solve the quadratic equation (4x

^{2}+ 4)=0

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